A particle of mass `m` is released from rest from point `P` at `x = x_(0)` on X-axis from origin `O` and falls vertically along y-axis as shown in Fig. What is the magnitude of the torque acting on the particle at time `t`, when it is at the point `Q w.r.t.O` ?

A particle of mass m is released in vertical plane from a point P at x=x_(0) on the x -axis. It falls vertically parallel to the y -axis. Find the torque tau acting on the particle at a time about origin.

In Fig. 10-73, a particle of mass m is released from rest at point A, at distance b from the origin, and falls parallel to a vertical y axis. As a function of time t and with respect to the origin, find the magnitudes of (a) the torque tau on the particle due to the gravitational force and (b) the angular momentum L of the particle. ( c) From those results, verify that tau=dL//dt .

A particle of mass m is released from rest at point A in the figure falling freely under gravity parallel to the vertical Y -axis. The magnitude of angular momentum of particle about point O when it reaches B is (where OA=b and AB=h )

A particle of mass m is released from rest at point A in Fig., falling parallel to the (vertical) y -axis. Find the angular momentum of the particle at any time t with respect to the same origin O .

v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

A point particle of mass m is released from a distance sqrt(3)R along the axis of a fixed ring of mass M and radius R as shown in figure. Find the speed of particle as it passes through the centre of the ring.

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s ?

A small particle of mass m is projected at an angle theta with x-axis with initial velocity upsilon_(0) in x-y plane as shown in Fig. Calculate the momentum of the particle at t lt (upsilon_(0) sin theta)/(g) .

A particle of mass m is projected from origin O with speed u at an angle theta with positive x-axis. Positive y-axis is in vertically upward. Direction. Find the angular momentum of particle at any time t about O before the particle strkes the ground again.