The moment of inertia of a copper disc, ...

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

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The moment of inertia of a disc rotating about an axis passing through its centre and perpendicular to its axis is 20 kgm^(2) . If its rotational K.E. is 10 J, then its angular momentum will be

The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is I . Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is 100kgm^(2) . What is the moment of inertia of the ring about its diameter ?

The moment of inertia of a circular disc about an axis passing through its centre and perpendicular to the plane is 4 kg m^(2) . Its moment of inertia about the diameter is

The moment of inertia of an thin circular disc about an axis passing through its center and perpendicualr to its plane, is l. Then, the moment of intertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

The moment of inertia of ring about an axis passing through its diameter is I . Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is

The Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is 1 / 2 MR^2 . Derive the values of moment of inertia of the disc about its diameter and about an axis tangential to the disc lying on its plane ?

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.

The moment of inertia of a thin uniform rod about an axis passing through its centre and perpendicular to its length is I_(0) . What is the moment of inertia of the rod about an axis passing through one end and perpendicular to the rod ?

The surface mass density of a disc of radius a varies with radial distance as sigma = A + Br where A & B are positive constants then moment of inertia of the disc about an axis passing through its centre and perpendicular to the plane

SL ARORA-System of particles & rotational Motion-EXERCISE

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