The earth has a mass of `6 xx 10^(24) kg` and a radius of `6.4 xx 10^(6)m`. Calculate the amount of work that must be done to slow down its rotation so that duration of day becomes `30` hrs instead of 24 hours.
Moment of inertia of earth `= (2)/(5)MR^(2)`.

The mass of earth is 6 xx 10^(24)kg and radius is 6400 km. How much amount of work will be done to make the duration of day its 20 hours rather than 24 hours.

The mass of the Earth is 6 xx 10^(24) kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth.

Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth = 5.98 xx 10^(27) kg, mean radius of the earth =6.37 xx 10^(6)m,M.I of the earth = (2)/(5)MR^(2) .

If earth is taken as a sphere of radius 6400 km and mass 6xx10^(24) kg, what would be the value of g on the surface of earth ?

The mass of the earth is 6.0 xx 10^(24) kg and its radius is 6.4 xx 10^(6) m . How much work will be done in taking a 10 kg body from the surface of the Earth to infinity ? What will be the gravitational potential energy of the body on the Earth's surafce ? G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

The mass and radius of the earth are 5.975 xx 10^24 kg and 6.37xx 10^6 m respectively. Calculate the average earth's density to correct significant figures. Take pi=3.142 .

How much below the surface of Earth does the acceleration due to gravity become 70% of its value on the surface of Earth. Radius of Earth = 6.4 xx 10^(6) m .

Calculate rotational K.E. of earth about its own axis, taking it to be a sphere of mass 6 xx 10^(24) kg and radius 6400 km .

The radius of the earth is 6.37 xx 10^(6) m and its mass is 5.975 xx 10^(24) kg . Find the earth's average density to approopriate significant figures.

Calculate the angular momentum of earth rotating about its own axis. Take Radius of earth =6.4xx10^(6)m Mass of earth =5.97xx10^(24)kg