Relate torque with angular acceleration

Two masses are attached to a rod end to end . If torque is applied they rotate with angular acceleration alpha . If their distances are doubled and same torque is applied, then they move with angular acceleration.

The torque needed to produce an angular acceleration of 18rad/ "sec"^2 in a body of moment of inertia 2.5kg- m^2 would be -

Relation between Torque and Angular Acceleration || Ladder Problem

If a wheel has mass 70 kg and radius of gyration 1 m, then the torque required an angular 1 m, then the torque required an angular acceleration of "2 rev"//s^(2) will be

A disc of radius 2m and mass 200kg is acted upon by a torque 100N-m. Its angular acceleration would be

The moment of inertia of a body is 2.5 kg m^(2) . Calculate the torque required to produce an angular acceleration of 18 rad s^(-2) in the body.

8 kg wheel has radius of gyration (1/4) m. The torque required to give it an angular acceleration of 4 rad//s^(2) , is

Obtain an expressing for torque acting on a body rotating with uniform angular acceleration.

A particle is at a distance r from the axis of rotation. A given torque tau produces some angular acceleration in it. If the mass of the particle is doubled and its distance from the axis is halved, the value of torque to produce the same angular acceleration is -