A torque of `2.0 xx 10^(-4)` Nm is applied to produce an angular acceleration of `4 "rad s"^(-2)` in a rotating body. What is the moment of inertia of the body ?

The torque needed to produce an angular acceleration of 18rad/ "sec"^2 in a body of moment of inertia 2.5kg- m^2 would be -

If a torque of magnitude 100 Nm acting on a rigid body produces an angular acceleration of 2 rad//s^(2) , then the moment of inertia of that body will be

A torque of magnitude 2000 Nm acting on a body produces an angular acceleration of 20" rad/s"^(2) , The moment of inertia of the body is

A constant torque of 31.4 Nm is applied to a pivoted wheel. If the angular acceleration of the wheel is 2pi" rad/s"^(2) , then its moment of inertia is

A wheel of radius 10 cm can rotate freely about its centre as shown in figure. A stirng is wrapped over its rim and is ulle dby a force of 5.0 N. It is found that the torque roduces an angular acceleration 2.0 rad/s^2 in the wheel. Calculate the moment of inertia of the wheel.

The torque acting is 2000 Nm with an angular acceleration of 2rad//s^(2) . The moment of inertia of body is

A torque of magnitude 400 N.m, acting on a body of mass 40 kg, Produces an angular acceleration of 20 rad/ s^(2) . Calculate the moment of inertia and radius of gyration of the body.