Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth `= 5.98 xx 10^(27)` kg, mean radius of the earth `=6.37 xx 10^(6)m,M.I` of the earth `= (2)/(5)MR^(2)`.

The value of angular momentum of the earth rotating about its own axis is

Calculate the angular momentum of earth rotating about its own axis. Take Radius of earth =6.4xx10^(6)m Mass of earth =5.97xx10^(24)kg

Calculate angular momentum of earth rotating about its axis. Take I = (2)/(5)MR^(2) , where M = 6 xx 10^(24) kg and R = 6400 Km .

A mango of mass 0.3 kg falls from a tree. Calculate the acceleration of the mango towards the earth. Also calculate the acceleration of the earth towards the mango. Take, Mass of the earth = 5.983 xx 10^(24) kg Radius of the earth = 6.378 xx 10^(6) m G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)

An apple of mass 0.25 kg falls from a tree . What is the acceleration of the apple towards the earth ? Also calculate the acceleration of the earth towards the apple . Mass of the earth = 5.983 xx 10^(24) kg , Radius of the earth = 6.378 xx 10^(6) m and G = 6.67 xx 10^(-11)Nm^(2) kg^(-2)

Calculate the mass and density of the earth. Given that Gravitational constant G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) , the radius of the earth = 6.37 xx 10^(6) m and g = 9.8 m//s^(2) .

Calculate the pressure caused by gravitational copmression at the centre of the earth . Express the result in terms of standard atmospheric pressure .Mass of the earth = 6.0 xx 10^(24) kg , radius of the earth = 6.4 xx 10^(6) m and g ( at the surface of the earth ) =9.8 m s^(-2) . 1 standard atmospheric pressure = 10^(5) Nm^(-2) .

Calculate rotational K.E. of earth about its own axis, taking it to be a sphere of mass 6 xx 10^(24) kg and radius 6400 km .

A synchronous satellite goes around the earth one in every 24 h. What is the radius of orbit of the synchronous satellite in terms of the earth's radius ? (Given: Mass of the earth , M_(E)=5.98xx10^(24) kg, radius of the earth, R_(E)=6.37xx10^(6)m , universal constant of gravitational , G=6.67xx10^(-11)Nm^(2)kg^(-2) )

A rocket is fired vertically with a speed of 5 kms^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the earth ? Mass of earth= 6.0xx10^(24) kg, mean radius of the earth = 6.4xx10^(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2).