An ice skater spins with arms outstretched at 1.9 rps. Her moment of inertia at this instant is 1.33 kg `m^2`. She pulls in her arms to increase her rate of spin. If the moment of inertia is 0.48 kg `m^2` after she pulls in her arms, what is her new rate of rotation ?

An ice skater has her arms outstretched and is spinning with a rate of 2 rotations per second. Her moment of inertia at this instant is 1.48kgm^(2) . She then pulls her arms inside to increase her rate of spin and her moment of inertia becomes 0.56kgm^(2) . Calculate her new rate of rotation.

A battet dancer spins with 2.8 rps with her arms out stretched. When the moment of inertia about the same axis becomes 0.7 l. the new rate of spin is

An ice skater starts a spin with her arms stretched out to the sides. She balances on the tip of one skate to turn without friction. She then pulls her arms in so that her moment of inertia decrease by a factor of 2 . In the process of her doing so, what happens to her kinetic energy ?

A ballet dancer spins about a vertical axis at 120 rpm with arms out stretched. With her arms fold the moment of inertia about the axis of rotation decreases by 40% . What is new rate of revolution?

An ice skater spins at 3pi" rad s"^(-1) with hers arms extended. If her moment of inertia with arms folded is 75% of that with arms extended, her angular velocity when she fold her arms is

A ballet dancer spins about a vertical axis at 60 rpm with arms outstretched. When her arms are folded the angular frequency increases to 90 rpm . Find the change in her moment of inertia.

A sphere of mass 5kg and diameter 2 m rotates about a tangent. What is its moment of inertia in kg m^(2) ?

The rotational kinetic energy of two bodies of moment of inertia 9 kg m^(2) and 1kg m^(2) are same . The ratio of their angular momenta is