Two balls of mass `m` each are placed at the two vertices of an equilateral triangle. Another ball of mass `2m` is placed at the third vertex of the triangle. Locate the centre of mass of the system.

Two charge +Q each are placed at the two verticles of an equilateral triangle of side a .The intensity of electric field at the third vertex is

Three equal masses 2m each are placed at the vertices an equilateral triangle PQR (i) What is the force acting on a mass m placed at the centroid G of the triangle ? (ii) What is the force on mass m if the mass at the vertex P is quadrupled ? Take PG = QG = RG = 1m

Three equal masses of 1 kg each are placed at the vertices of an equilateral triangle PQR and a mass of 2 kg is placed at the centroid O of the triangle which is at a distance of sqrt(2)m from each of the vertices of the triangle. The force, in newton, acting on the mass of 2 kg is :

Three equal masses of 2kg each are placed at the vertices of an equilateral triangle and a mass of 4 kg is placed at the centroid of the triangle which is at a distance of sqrt(2) m from each of the vertices of the triangle. The force, (in newton) acting on the mass of 4 kg is

Two charge +Q,-Q are placed at the two verticels of an equilateral triangle of side 'a' . Then the intensity of electric field at the third vertex is

If two particles each of mass m are placed at the two vertices of an equilateral triangle of side a , then the resultant gravitational force on mass m placed at the third vertex is