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The Moment of inertia of a disc about an...

The Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is 1 / 2`MR^2`. Derive the values of moment of inertia of the disc about its diameter and about an axis tangential to the disc lying on its plane ?

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Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is frac (1)(2)MR^2 . Determine the moment of inertia of this disc about its diameter and about a tangent perpendicular to its plane.

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Knowledge Check

  • Moment of inertia of a circular ring about an axis through its centre and perpendicular to its plane is

    A
    `I = (1)/(2) MR^2`
    B
    `I = MR^2`
    C
    `I = (3)/(2) MR^2`
    D
    `I = (5)/(2) MR^2`

  • The radius of gyration of a disc about its axis passing through its centre and perpendicular to its plane is

    A
    `R//sqrt(2)`
    B
    R/2
    C
    `sqrt(2)` R
    D
    2R

  • The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

    A
    increases if its temperature is increased
    B
    changes if its axis of rotation is changed
    C
    increases if its angular velocity is increased
    D
    both (a) and (b) are correct

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    The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is I . Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

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