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The moment of inertia of a uniform circu...

The moment of inertia of a uniform circular disc about a tangent in its own plane is `5/4MR^2` , where M is mass and R is the radius of the disc. Find its moment of inertia about an axis through its centre and perpendicular to its plane.

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Knowledge Check

  • Moment of inertia of a circular ring about an axis through its centre and perpendicular to its plane is

    A
    `I = (1)/(2) MR^2`
    B
    `I = MR^2`
    C
    `I = (3)/(2) MR^2`
    D
    `I = (5)/(2) MR^2`

  • A uniform disc of mass 5 kg has a radius of 0.5 m. Its moment of inertia about an axis passing through a point on its circumference and perpendicular to its plane is

    A
    `"1.25 kg - m"^(2)`
    B
    `"0.5 kg - m"^(2)`
    C
    `"4 kg - m"^(2)`
    D
    `"1.875 kg - m"^(2)`

  • The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

    A
    increases if its temperature is increased
    B
    changes if its axis of rotation is changed
    C
    increases if its angular velocity is increased
    D
    both (a) and (b) are correct

    • Similar Questions

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    Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

    The moment of inertia of a disc of mass M and radius R about a tangent to its rim in its plane is

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    The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameters is 1/4 MR^(2) . What is the moment of inertia of the disc about an axis passing through its centre and normal to the disc?

    Moment of inertia of a uniform quarter disc of radius R and mass M about an axis through its centre of mass and perpendicular to its plane is :

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