The moment of inertia of a ring about one of its diameters is I.What willbe its moment of inertia about a tangent parallel to the diameter ?

Options

A. 4I
B. 2I
C. `frac(3)(2)I`
D. 3I

Explanation

To find the moment of inertia of a ring about a tangent parallel to its diameter, we can use the parallel axis theorem. Here's a step-by-step solution:

### Step 1: Understand the Given Information
We know that the moment of inertia of the ring about one of its diameters is given as \( I \). For a ring, the moment of inertia about its diameter is calculated as:
\[ I = \frac{1}{2} m r^2 \]
where \( m \) is the mass of the ring and \( r \) is its radius.
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