Four solid sphereas each of diameter `sqrt(5) cm` and mass `0.5 kg` are placed with their centres at the corners of a square of side `4 cm`. The moment of inertia of the system about the diagonal of the square is `N xx 10^(-4) kg-m^(2)`, the `N` is -

Four solid spheres each of diameter sqart5 cm and mass 0.5 kg are placed with their centers at the corners of a square of side 4cm. The moment is Nxx10^(-4)kg - m^2 , then N is .

Four spheres of diameter 2a and mass M are placed with their centres on the four corners of a square of side b. Then moment of inertia of the system about an axis about one of the sides of the square is :-

Four spheres,each of mass "m" and radius "r" ,are placed with their centres on the four corners of a square of side "b" .The moment of inertia of the system about any side of the square is

Four spheres each of mass M and diameter 2r , are placed with their centers on the four corners of a square of side a( gt 2r) . The moment of inertia of the system about one side of the square is

Four spheres, each of diameter 2a and mass M are placed with their centres on the four corners of a square of side b . Calculate one side of the square taken as the axis.

Four spheres of diameter a and mass m each are arranged at the corners of a square of side 1. Calculate the moment of inertia of the system about CD taken as its axis.

Four identical solid spheres each of mass 'm' and radius 'a' are placed with their centres on the four corners of a square of side 'b'. The moment of inertia of the system about one side of square where the axis of rotation is parallel to the plane of the square is :