Find the value of g at a height of 400 km above the surface of the earth . Given radius of the earth , R = 6400 km and value of g at the surface of the earth = `9.8 ms^(-2)`.

Find the weight of a body at a height of 100 km above the surface of earth. The radius of earth is 6,400 km and the body weighs 90 N on earth's surface.

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2

Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).

Compare the weight of a body 100 km above and 100 km below the surface of the earth . Radius of the earth = 6400 km .

Calculate the escape velocity for an atmospheric particle 1600 km above the earth's surface, given that the radius of the earth is 6400 km and acceleration due to gravity on the surface of earth is 9.8 ms^(-2) .

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .

A mine worker measures his weight inside a mine and finds that it has decreased by 0.05% of that on the surface of the Earth. Then,find the depth of the mine (Take the radius of the Earth = 6400 km and acceleration due to gravity on the surface of the Earth, g = 9.8 ms^(-2) ).

Calculate the escape speed for an atmospheric particle 1600 km above the Earth's surface, given that the radius of the Earth is 6400 km amd acceleration due to gravity on the surface of Earth is 9.8 ms^(-2) .

At what height above the surface of earth the value of "g" decreases by 2 % [ radius of the earth is 6400 km ]

A rocket is launched vetically from the surface of the earth with an initial velocity of 10 kms^(-1) . How for above the surface of the earth would it go ? Radius of the earth =6400 km and g=9.8 ms^(-2) .