Home
Class 11
PHYSICS
Calculate the depth below the surface of...

Calculate the depth below the surface of the earth where acceleration due to gravity becomes half of its value at the surface of the earth . Radius of the earth = 6400 km.

Promotional Banner

Topper's Solved these Questions

  • FLUIDS AT REST

    SL ARORA|Exercise Problem|19 Videos
  • FLUIDS AT REST

    SL ARORA|Exercise Problem for self practice|69 Videos
  • FLUIDS IN MOTION

    SL ARORA|Exercise All Questions|117 Videos

Similar Questions

Explore conceptually related problems

How much below the surface of the earth does the acceleration due to gravity become 70% of its value at the surface of the earth ? Radius of the earth is 6400 km

At what depth below the surface of earth the acceleration due to gravity becomes one-third of its value at the surface of earth ?

How much below the surface of the earth does the acceleration due to gravity become 1% of its value at the earth's surface ? Radius of the earth=6400 km.

Calculate the depth below the surface of the earth where the acceleration due to gravity is 2% of its value at the earth's surface. Take, Radius of earth = 6,400 km

At what depth below the surface does the acceleration due to gravity becomes 70% of its value in the surface of earth ?

At what depth below the surface of the earth acceleration due to gravity will be half its value at 1600 km above the surface of the earth ?

The depth from the surface of the earth where acceleration due to gravity is 20% of its value on the surface of the earth is (R = 6400 km)

At what depth below the surface of the earth, acceleration due to gravity g will be half its value 1600km above the surface of the earth

At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ?

SL ARORA-FLUIDS AT REST-Problem for self practice
  1. Calculate the depth below the surface of the earth where acceleration ...

    Text Solution

    |

  2. A force of 40 N is applied on a nail , whose tip has an area of cross-...

    Text Solution

    |

  3. Atmospheric pressure is 1.01 xx 10^(5) Pa. How large a force does the ...

    Text Solution

    |

  4. The force on a Phonograph needle is 1.2 N. the point has a circular cr...

    Text Solution

    |

  5. A cylinderical vessel contaning liquid is closed by a smooth piston of...

    Text Solution

    |

  6. The cross-section of two piston in hydraulic press are 2cm^(2) "and" 1...

    Text Solution

    |

  7. The average mass that must be lifted by a hydraulic press is 80 "kg".I...

    Text Solution

    |

  8. In a hydraulic press used for compressing cotton the area of the pisto...

    Text Solution

    |

  9. An automobile sack is lifted by a hydraulic jack that consists of two ...

    Text Solution

    |

  10. What is the minimum pressure required to force blood from the heart to...

    Text Solution

    |

  11. A column of water 40 cm height supports a 30 cm column of an unknown l...

    Text Solution

    |

  12. If the water pressure gauge shows the pressure at ground floor to be 2...

    Text Solution

    |

  13. A cylinderical jar of cross-sectional area of 50 cm^(2) is filled with...

    Text Solution

    |

  14. Water is filled in a flask upto a height of 20cm. The bottom of the fl...

    Text Solution

    |

  15. The density of asir ner earth's surface is 1.3kgm^-3 and the atmospher...

    Text Solution

    |

  16. A vertical U-tube of uniform inner cross-section contains mercury in ...

    Text Solution

    |

  17. Two liquids of specific gravity 1.2 "and" 0.84 are poured into the l...

    Text Solution

    |

  18. The area of cross-section of the wider tube shown in fig., is 800cm^(2...

    Text Solution

    |

  19. A barometer kept in an elevator accelerating upwards reads 76 cm of Hg...

    Text Solution

    |

  20. How much will a body of 70 N weight in water if it displaces 20 ml of...

    Text Solution

    |

  21. A solid weighs 6 kg in air. If its density is 2000 "kg" m^(3) what wil...

    Text Solution

    |