If the Earth were a perfect sphere of radius `6.37 xx 10^(6) m`, rotating about its polar exis with a period of `1` day `(= 8.64 xx 10^(4) s)` how much would the acceleration due to gravity differ from the poles to equator?

Considering the earth to be a perfect sphere of radius 6.4 xx 10^(6)m , rotating about its axis with a period of 1 day (= 8.64 xx 10^(4)s) , calculate the difference in acceleration due to gravity at the poles and the equator.

Suppose Earth is perfect sphere of radius 6.4 xx 10^(6) m . It is rotating about its polar axis with a period of 1 day. What is the difference in the value of acceleration due to gravity on pole and at a place of latitude 60^(@) ?

The mass of the Earth is 6 xx 10^(24) kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth.

The radius of the moom is 1.7 xx 10^(6) m and its mass is 7.4 xx 10^(22) kg . If G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) , find the value of acceleration due to gravity on the surface of moon.

Mass of moon is 7.3 xx 10^(22) kg and its radius is 1.74 xx 10^(6) m. Find the value of the acceleration due to gravity on the moon.

If earth were to rotate on its own axis such that the weight of a person at the equator becomes half the weight at the poles, then its time period of rotation is (g = acceleration due to gravity near the poles and R is the radius of earth) (Ignore equatorial bulge)

The height above the surface of earth at which acceleration due to gravity is half the acceleration due to gravity at surface of eart is (R=6.4xx10^(6)m)

By considering earth to be non spherical. STATEMENT -1 : As one moves from equator to the pole of earth, the value of acceleration due to gravity increases. and STATEMENT -2 : If earth stops rotating about its own axis, the value of acceleration due to gravity will be same at pole and at equator.

Assuming the mass of Earth to be ten times the mass of Mars, its radius to be twice the radius of Mars and the acceleration due to gravity on the surface of Earth is 10 m//s^(2) . Then the accelration due to gravity on the surface of Mars is given by