At a point above the surface of the earth, the gravitational potential is `-5.12xx10^(7)JKg^(-1)` and the acceleration due to gravity is `6.4 ms^(-2)`. Assuming the mean radius of the earth to be 6400 km, calculate the heights of this point above the earth's surface.

At a point above the surface of the earth, the gravitational potential is -5.12 xx 10^(7) J/kg and the acceleration due to gravity is 6.4 m//s^(2) . Assuming the mean radius of the earth to be 6400 km, calculate the height of the point above the earth's surface.

At a point above the surface of Earth, the gravitational potential is -5.12 xx 10^(7) J kg^(-1) and the acceleration due to gravity is 6.4 ms^(-2) . Assuming the mean redius of the earth to be 6400 km , calcualte the height of this point above the Earth's surfcae.

The gravitational potential at a point above the surface of earth is -5.12times10^(7)J//kg and the acceleration due to gravity at that point is 6.4m//s^(2) .Assume that the mean radius of earth to be 6400km" .The height of this point above the earth's surface is :

The gravitational potential at some point above the surface of the earth is -4.32 xx 10^(7) J//kg and acceleration due to gravity at that point is 5.4 m//s^(2) . If the mean radius of earth is 6.37 xx 10^(6)m , then find the height of this point from the earth's surface.

At what height from the surface of earth the gravitation potential and the value of g are - 5.4 xx 10^(7) J kg^(-2) and 6.0 ms^(-2) respectively ? Take the radius of earth as 6400 km :

At what height from the surface of earth the gravitation potential and the value of g are - 5 . 4 xx 10^(7) J kg^(-2) and 6 . 0 ms^(-2) respectively. Take the radius of earth as 6400 km

The height above the surface of earth at which acceleration due to gravity is half the acceleration due to gravity at surface of eart is (R=6.4xx10^(6)m)