Calculate the escape velocity for an atmospheric particle 1600 km above the earth's surface, given that the radius of the earth is 6400 km and acceleration due to gravity on the surface of earth is 9.8 `ms^(-2)`.

Calculate the escape speed for an atmospheric particle 1600 km above the Earth's surface, given that the radius of the Earth is 6400 km amd acceleration due to gravity on the surface of Earth is 9.8 ms^(-2) .

Calculate the escape speed of an atmospheric particle which is 1000 km above the earth's surface . (Radius of the = 6400 km nd acceleration due to gravity = 9.8 ms ^(-2)

A particle is taken to a height R above the earth's surface, where R is the radius of the earth. The acceleration due to gravity there is

The mass of the Earth is 6 xx 10^(24) kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth.

Find the value of g at a height of 400 km above the surface of the earth . Given radius of the earth , R = 6400 km and value of g at the surface of the earth = 9.8 ms^(-2) .

A mine worker measures his weight inside a mine and finds that it has decreased by 0.05% of that on the surface of the Earth. Then,find the depth of the mine (Take the radius of the Earth = 6400 km and acceleration due to gravity on the surface of the Earth, g = 9.8 ms^(-2) ).

What should be the length of the day so that the weight of a body on the equator of earth becomes zero ? Given that radius of earth is 6400 km and acceleration due to gravity on its surface is 9.8 m//s^(2)

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2