A body is to be projected vertically upwards from earth's surface to reach a height of `9R`, where `R` is the radius of earth. What is the velocity required to do so? Given `g=10ms^(-2)` and radius of earth`=6.4xx10^(6)m`.

If a body is to be projected vertically upwards from earth's surface to reach a height of 10R where R is the radius of earth. The velocity required to be si is

A body is projected vertically upward from the surface of the earth, then the velocity-time graph is:-

Calculate the velocity with which a body must be thrown vertically upward from the surface of the earth so that it may reach a height of 10R , where R is the radius of the earth and is equal to 6.4 xx 10^(6)m. (Given: Mass of the earth = 6 xx 10^(24) kg , gravitational constant G = 6.7 xx 10^(-11) N m^(2) kg^(-2) )

A body is projected vertically upwards from the earth's surface. The body reaches a height equal to one half of radius of earth. Calculate the initial speed with which the body was projected initially. Radius of earth = 6,400 km Mass of earth = 6 xx 10^(24) kg

The initial velocity v_(i) required to project a body vertically upward from the surface of the earth to reach a height of 10R, where R is the radius of the earth, may be described in terms of escape velocity v_(e ) such that v_(i)= sqrt((x)/(y)) xx v_(e ) . The value of x will be __________ .

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

A body of mass m is lifted from the surface of earth of height equal to R//3 where R is the radius of earth, potential energy of the body increases by

A body is projected vertically upwards with a speed of sqrt((GM)/R) ( M is mass and R is radius of earth ) . The body will attain a height of

A body is released from a height 5R where R is the radius of the earth. Then that body reaches the ground with a velocity equal to

At what height h above the earth's surface, the value of g becomes g/2 (where R is the radius of the earth)