One of the satellite of jupiter, has an orbital period of `1.769` days and the radius of the orbit is `4.22 xx 10^(8) m`. Show that mass of jupiter is about one thousandth times that of the mass of the sun. (Take `1` year `= 365.15` mean solar day).

One of the satellite of jupiter, has an orbital period of 1.769 days and the radius of the orbit is 4.22 xx 10^(8) m . Show that mass of jupiter is about one thousandth times that of the radius of the sun. (Take 1 year = 365.15 mean solar day).

A satellite of Jupiter has a period of 1.77 day and orbital radius of 4.22xx10^(8)m . Find the mass of Jupiter.

The mean orbital radius of the Earth around the Sun is 1.5 xx 10^8 km . Estimate the mass of the Sun.

The period of moon around the earth is 27.3 days and radius of the orbit is 3.9 xx 10^(5) km . G=6.67 xx 10^(-11) Nm^(-2)kg^(-2) , find the mass of the earth.

The time period of the moon is T= 27.3 days and radius of orbit is R_(m)=3.84xx10^(8)m The value of centripetal acceleartion due to earht 's gravity is

The radius of a planet is 74 xx 10^(3) km . A satellite of this planet completes one revolution in 16.7 days. If the radius of the orbit of satellite is 27 times the radius of planet, then the mass of planet is

The time period of jupiter is 11-6 year, how far is jupitor from the sun. Distance of earth from the sun is 1.5 xx 10^(11) m .

Calculate the speed of Jupiter if the mass of Jupiter is 1.9 xx 10^(27) kg . Distance from the sun is 7.8 xx 10^(11)m and the mass of the sun is 2 xx 10^(30) kg .

How will you weight the sun, i.e. estimate its mass ? You will need to know the period of one of its planets and the radius of the planetary orbit. The mean orbit radius of the earth around the sun is 1.5 xx 10^(8)km , then the mass of the sun would be calculated as

The mean radius of the earth's orbit around the sun is 1.5 xx 10^(11)m and that of the orbit of mercury is 6 xx 10^(10)m . The mercury will revolve around the sun is nearly