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Mass of moon is 1//81time that of earth ...

Mass of moon is `1//81`time that of earth and its radius is `1//4` the earth's radius. If escape velocity at surface of earth is `11.2 km/s`, then its value at surface of moon is

A

`0.14km//s`

B

`2.5km//s`

C

`0.5km//s`

D

`5km//s`

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Knowledge Check

  • Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon is

    A
    0.14 km / s
    B
    0.5 km / s
    C
    2.5 km / s
    D
    5 km / s

  • The mass of the moon is 7//81 th of earth 's mass and its radius is 1//4 th that of the earth if the escape velocity from the earth surface is 11.2 kms^(-1) its value for the moon will be

    A
    `0.15 kms^(-1)`
    B
    `5 kms^(-1)`
    C
    `2.5 kms^(-1)`
    D
    `0.5 kms^(-1)`

  • The mass of moon is (1)/(81) of earth 's mass and its radius is (1)/(4) of that of earth .If the escape velocity from the earth 's surface is 11.2km/s , is value for the moon is :

    A
    0.14 km/s
    B
    0.5 km/s
    C
    2.5 km/s
    D
    5.0 km/s

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