On Earth value of `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.
What is its value on Moon, where `g` is nearly one-sixth than that of Earth?

One earth, value of G=6.67 xx 10^(11)Nm^(2)kg^(2) . What is its value on moon, where g is nearly (1)/(6) th that of earth ?

The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

The radius of the moom is 1.7 xx 10^(6) m and its mass is 7.4 xx 10^(22) kg . If G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) , find the value of acceleration due to gravity on the surface of moon.

The weight of a person on the Earth is 80 kg . What will be his weight on the Moon ? Mass of the Moon = 7.34 xx 10^(22) kg , radius = 1.75 xx 10^(6) m and gravitational constant = 6.67 xx 10^(-11) N m^(2) kg^(-2) . What will be the mass of the person at the Moon and acceleration due to gravity there ? If this person can jump 2 m high on the Earth, how much high can he jump at the Moon ?

The value of G=6.67 xx 10^(-11) N m^(2) kg^(-2) " and " g=9.8 m s^(-2) . The unit of g//G in C.G.S system is "_______"

Calculate the mass of the sun if the mean orbital radius of Jupiter around the sun is 7.8 xx 10^(11) m . Take G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) Time period of revolution = 12 years according to earth

If the value of universal gravitational constant is 6.67xx10^(11) Nm^2 kg^(-2), then find its value in CGS system.