The mass and diameter of a planet have twice the value of the corresponding parameters of earth. Acceleration due to gravity on the surface of the planet is

The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))

A planet has a mass M_(1) and radius R_(1). The value of acceleration- due to gravity on its surface is g_(1). There is another planet 2, whose mass and radius both are two times that of the first planet. Which one of the following is the acceleration due to gravity on the surface of planet 2?

The mass of a planet is twice the mass of earth and diameter of the planet is thrie the diameter of the earth, then the acceleration due to gravity on the planet's surface is

The mass and diameter of a planet are half of thast of the earth. The ratio of gravitational potential energy of a body on the surface of the planet to that on the surface of the earth is

A simple pendulum makes 20 oscillations in one second on the surface of the earth. Determine the time period of the simple pendulum on the surface of a planet where the acceleration due to gravity is one fourth of the acceleration due to gravity on the surface of the earth .

The density of a newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth be R, then radius of the planet would be

Suppose a planet exists whose mass and radius both, are half those of earth. Calculate the acceleration due to gravity on the surface of this planet.