A brass rod at `30^@C` is observed to be 1 metre long when measured by a steel scale which is correct at `0^@C`. Find the correct length of the rod at `0^@C`. Given `alpha` for steel `=0.000012` per `^@C` and `alpha` for brass `=0.000019` per `^@C`.

A steel tape measures that length of a copper rod as 90.0 cm when both are at 10^(@)C , the calibration temperature, for the tape. What would the tape read for the length of the rod when both are at 30^(@)C . Given alpha_("steel")=1.2xx10^(-5)" per".^(@)Cand alpha_(Cu)=1.7xx10^(-5)per .^(@)C

A steel scale measures the length of a copper wire as 80.0 cm when both area at 20^(@)C (the calibration temperature for scale). What would be the scale read for the length of the wire when both are at 40^(@)C ? (Given alpha_("steel") = 11 xx 10^(-6) per ^(@)C and alpha_("copper") = 17 xx 10^(-6) per^(@)C )

Consider a brass rod and a steel rod (80 cm longer than brass rod) at 0^(@)C . It is observed that on increasing temperatures of the two rods by same amount difference in lengths of the two rods does not change. Given that the thermal coefficient of linear expansion for steel and brass are 11xx10^(-6).^(@)C^(-1) and 19xx10^(-6).^(@)C^(-1) respectively. The sum of lengths of the two rods at 0^(@)C is

A Barometer with brass scale, which is correct at 0^(@)C , reads 75cm on a day when the air temperature is 20^(@)C . Calculate correct reading at 0^(@)C . (Coefficient of real expansion of mercury =0.00018//^(@)C and coefficient of linear expansion of brass =0.000189//^(@)C .)

A barometer with a brass scale correct at 0^(@)C reads 70 cm of mercury on a day when the air temperature is 40^(@)C . The correct reading at 0^(@)C is (Coefficient of real exapansion of mercury is 0.00018//^(@)C and coefficient of linear expansion of brass is 0.00018//^(@)C)

A brass scale gives correct length at 0^(@)C . If the temperature by 25^(@)C and the length read by the scale is 10 cm . Then the actual length will be

How much should the temperature of a brass rod be increased so as to increse its length by 1% ? Given alpha for brass is 0.00002 .^(@)C^(-1) .