A clock having a brass pendulum beats seconds at `30^@C`. How many seconds will it lose or gain per day when temperature falls to `10^@C`? Given `alpha` for brass `=(1.9xx10^-5)^@C^-1`.

Take the values of (prop) from table 20.2 . A pendulum clock of time period 2 s gives the correct time at 30^@ C . The pendulum is made of iron. How many seconds will it lose or gain per day when the temperature falls tp 0^@ C ? alpha _(Fe) = 1.2 xx 10^-5 (.^@ C)^-1 .

A clock which keeps correct time at 20^@C has a pendulum rod made of brass . How many seconds will it gain or lose per day when temperature falls to 0^@C ? [alpha=18xx10^(-6)//^@C]

A clock with an Iron Pendulum keeps correct time at 20^(@)C How much will it lose or gain if temperature changes to 40^(@)C ? [Given cubical expansion of iron =36xx10^(-6)""^(@)C^(-1) ]

If the length of a second's pendulum is increased by 1% , how many seconds will it loss or gain in a day ?

A pendulum clock gives correct time at 20^° C. How many seconds will it lose per day at 40^° C? (alpha = 5 xx 10^-6 /°C)

A clock while keeps correct time at 30^(@)C has a pendulum rod made of brass. The number of seconds it gains (or) looses per second when the temperature falls to 10^(@)C is [ alpha of brass = 18 xx 10^(-6//@)C ]

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A clock with an iron pendulum keeps correct time at 20^(@)C . How much time will it lose or gain in a day if the temperature changes to 40^(@)C . Thermal coefficient of liner expansion alpha = 0.000012 per^(@)C .