Calculate the heat required to convert 3 kg of ice at `-12^(@)C` kept in a calorimeter to steam at `100^(@)C` at atmospheric pressure. Given,
specific heat capacity of ice = `2100 J kg^(-1) K^(-1)`
specific heat capicity of water = `4186 J kg^(-1)K^(-1)`
Latent heat of fusion of ice = ` 3.35 xx 10^(5) J kg^(-1)`
and latent heat of steam = ` 2.256 xx 10^(6) J kg^(-1)` .

Calcuate the heat required to convert 0.6 kg of ice at - 20^(@)C , kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given the specific heat capacity of ice =2100 j kg^(-1) K^(-1) , specific heat capacity of water =4186 j kg^(-1) K^(-1) latent heat ice =3.35xx10^(5) j kg^(-1) and latent heat of steam =2.256xx10^(6)j kg^(-1)

Specific heat capacity of water is ____ J kg^(-1) K^(-1) .

Calculate the amount of head required to convert 1.00kg of ice at - 10^(@)C into stream at 100^(@)C at normal pressure Specific heat of ice = 2100J kg^(-1)K^(-1) intent heat of fusion of ice = 3.36 xx 10^(5)Jkg^(-1) specific heat capacity of water = 4200 Jkg^(-1)k^(-1) and latent head of vaporisation of water = 2.25 xx 10^(6)J kg^(-1)

What will be the result of mixing 2kg of cooper at 100^(@)C with 0.75 kg of ice at 0^(@)C (Specific heat capacity of cooper =378J kg^(-1)K^(-1) specific heat capacity of water =4200 J kg^(-1)K^(-1) and specific latent heat of fusion of ice =336xx10^(3)Jkg^(-1) )

A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in beginning? Neglect heat losses. Given : Specific heat capacity of copper =0.42xx10^3 J kg^(-1) K^(-1) . Specific heat capacity of water =4.2 xx10^3 J kg^(-1) K^(-1) Specific heat of fusion of ice =3.36xx10^5 J kg^(-1) Latent heat of condensation of steam =22.5 xx 10^5 J kg^(-1)

What is the amount of heat 1 kg of ice from -5^(@)C" to "5^(@)C (Given, specific heat of ice =2.095 Kj kg^(1)""^(@)C^(-1) , specific heat of water =4.2 J g^(-1)""^(@)C^(-1), specifc latent heat of fusion of ice =336 J g^(-1) )

Calculate the entropy change when 1 kg of water is heated from 27^(@)C to 200^(@)C forming supper heated steam under constant pressure. Given specific heat of water = 4180 J Kg^(-1)K^(-1) and specific heat of steam = 1670 + 0.49 J kg^(-1)K^(-1) and latent heat of vaporisation =23 xx 10^(5) J kg^(-1) .