The temperature gradient in a rod 0.5 m long is `40^@C` per metre. The temperature of the hotter end is `30^@C`. What is the temperature of its colder end?

The temperature gradient in a rod of 0.5 m long is 80^(@)C//m . If the temperature of hotter end of the rod is 30^(@)C , then the temperature of the colder end is

The temperature gradient in a rod of 1m long is '100^@' C/m if the temperature of hotter end is '30^@' C, then the temperature of colder end is

The temperature gradient in a rod of 0.5 m length is 80^(@)C//m . It the temperature of hotter end of the rod is 30^(@)C , then the temperature of the cooler end is

The ends of a thin bar are maintained at different temperatures. The temperature of the cooler end is 11^(@)C , while the temperature at a point 0.13m from the cooler end is 23^(@)C and the temperature of the warmer end is 48^(@)C . Assuming that heat flows only along the length of the bar ( the sides are insulated), find the length of the bar.

Two rods of same dimensions, but made of different materials are joined end to end to end with their free end being maintained at 100^(@)C and 0^(@)C respectively. The temperature of the junction is 70^(@)C . Then the temperature of the junction if the rods are inerchanged will be equal to T^(@)C Find T :

In the figure-II temperature of inner surface of cylinder is 0^@C and temperature of outer surface is 100^@C . In figure-I temperature of one end of cylinder is 100^@C while another end is at 0^@C (dT)/(dr) =temperature gradient in radial direction at steady state in figure -II (dT)/(dl) =temperature gradient in linear direction at steady state in figure -I . both cylinder are made of uniform material

A Carnot cycle has an efficiency of 40% . Its low temperature resrvoir is at 7^(@)C . What is the temperature of source ?

The two rods show in figure have identical geomerical dimension.. They are in contact with two heat baths at temperature 100^(@)C . And 0^(@)C . The temperature of the junction is 70^(@)C . Find the temperature of the junction if the rods are interchanged.

The ratio of radiant energies radiated per unit surface area by two bodies is 16 : 1 , the temperature of hotter body is 1000 K , then the temperature of colder body will be

The temperature of a body falls from 40^° C to 30^° C in 10 minutes. If the temperature of surrounding is 15^° C, then time to fall the temperature from 30^° C to 20^° C