Assuming that a domestic refrigerator can be regarded as a reversivle engine working between the temperature of melting ice and that of the atmosphere `(170^(@)C)`, calculate the energy which muct be supplied to freeze one kilogram of water already at `0^(@)C`.

A refrigerator works between temperature of melting ice and room temperatures (17^(@)C) . The amount of energy (in kWh) that must be supplied to freeze I kg of water at 0^(@)C is

A Carnot engine works between temperature 0^(@)C and 100^(@)C . Calculate its efficiency.

In summer, Kamal decides to take a bath at noon. Temperature of the water in overhead tank is 45^(@)C so he decides to mix ince from refrigerator. The temperature of the ice in refrigerator. The temperature of the ice in refrigerator is 10^(@)C . How much ice will be needed to prepare 20 kg of water at 25^(@)C for bath? (Assume no loss to surrounding latent heat of fusion of ice =80cal//gm , specific heat of ice =0.5cal//gm^(@)C

A refrigerator is driven by 1000 W electric motor having an efficiency of 60% . The refrigerator is considerd as a reversible heat engine operating between 273K and 303K . Calculate the time required by it to freeze 32.5 kg of water at 0^(@)C . Heat losses may be rejected. Latent heat of fusion of ice = 336xx10^(3)J kg^(-1) .

A refrigerator freezes 5 kg of water at 0^(@)C into ice at 0^(@)C in a time internal of 20 minutes. Assume that the room temperature is 20^(@)C . Calculate the minimum power needed to accomplish it.

In a refrigerator, the low temperature coil of evaporator is at -23^@C and the compressed gas in the condenser has a temperature of 77^@C . The amount of electrical energy spent in freezing 1 kg of water at 0^@C is

Calculate the quantity of heat released during the conversion of10g of ice cold water ( temperature 0^(@)C ) into ice at the same temperature . ( Specific latent heat of freezing of water = 80 cal //g )

Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") What is the work done by the refrigerator in this process ( 1 "cal" = 4.2 "joule" )

Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") How many calories of heat are discarded to the room?