A sample of 0.1 g of water of 100^(@)C a...

A sample of `0.1 g` of water of `100^(@)C` and normal pressure `(1.013 xx 10^(5) N m^(-2))` requires 54 cal of heat energy to convert to steam at `100^(@)C`. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is

104.3 J

84.5 J

42.2 J

208.7 J

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A sample of 0.1 g of water at 100 and normal pressure (1.013 xx10^(5)Nm^(-2)) requires 54 cal of heat energy to convert to steam at 100^@C . If the volume of the steam produced is 167.1 c c the charge in internal energy of the sample is

A sample of 0.5 g water at 100°C and 1 atm pressure requires 270 cal heat energy to convert to steam at 100°C. If at the same pressure, volume of the steam produced is 835.5 cc then change in internal energy of the sample is (1 cal = 4.2 J, 1 atm 10^5 N/m^2 )

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Calculate amount of heat required to convert 1kg steam form 100^(@)C to 200^(@)C steam

1 gm of ice at 0^@C is converted to steam at 100^@C the amount of heat required will be (L_("steam") = 536 cal//g) .

At 100^(@)C the volume of 1 kg of water is 10^(-3) m^(3) and volume of 1 kg of steam at normal pressure is 1.671 m^(3) . The latent heat of steam is 2.3 xx 10^(6) J//kg and the normal pressure is 10^(5) N//m^(2) . If 5 kg of water at 100^(@)C is converted into steam, the increase in the internal energy of water in this process will be

SL ARORA-FLUIDS AT REST-Problem for self practice

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