Prove analytically that in the case of a closed organ pipe of length I, the frequencies of the vibrating air column are given by `nu =(2n + 1)(v//4L)`, where n is an integer.

Prove analytically that in the case of a closed organ pipe of length L the frequencies of the vibrating air column are given by v = (2n + 1) (v//4L) , where n is an integer.

Prove analytically that in the case of an open organ pipe of length L the frequencies of vibrating air column are given by v=n(v//2L) , where n is an integer.

An open and closed organ pipe have the same length the ratio pth mode of frequency of vibration of air in two pipe is

When a closed organ pipe of length l if the velocity of sound is v then the fundamental frequency will be

The fundamental frequency of a closed organ pipe is 'n' . If its length is doubled then frequency will become (neglecting end correction)

A closed organ pipe of length 1.2 m vibrates in its first overtone mode . The pressue variation is maximum at

A closed organ pipe of length 1.2 m vibrates in its first overtone mode. The pressure variation is maximum at

The frequency of vibration of air column in a pipe closed at one end is n_(1) and that of the one closed at both end is n_(2) . When both the pipes are joined to form a pipe closed atone end, the frequency of vibration of air column in it is (neglecting end correction )

Find the fundamental frequency of a closed pipe, if the length of the air column is 42 m . (speed of sound in air = 332 m/sec )