An open organ pipe produces a note of frequency 512 Hz at `15^@ C`, calculate the length of the pipe.Velocity of sound at `0^@C` is `335 ms^(-1)`.

At 20^(@) C, an open organ pipe produces a note of frequency 256 Hz. What will be the length of pipe if velocity of sound at 0^(@)C is 340 m/s ?

A pipe produces notes of frequencies 300Hz, 600Hz, 900 Hz , the pipe is

In open organ pipe, first overtone produced is of such frequency that length of the pipe is equal to

The length of an organ pipe open at both ends is 0.5m in Calculate the fundamental frequency of the pipe, if the velocity of sound in air be 350 ms^-1 ?

The second overtone of an open pipe beats with the seconds overtone of a closed pipe with a beat frequency of 3.2 Hz. If the fundamental frequency of closed organ pipe is 120 Hz, calculate the lengths of the pipes. Take, Velocity of sound in air = 320 m/s

An open organ pipe sounds a fundamental note of frequency of 230 Hz . It the speed of sound in air is 330 m//s ., then the length of the pipe is nearly-

An open organ pipe has a fundamental frequency of 300 Hz . The first overtone of a closed organ pipe has the same frequency as the first overtone of the open pipe . Find length of each pipe . The velocity of sound in air = 350 m//s .

Two organ pipes, open at both ends, are sounded together and six beats per second are produced. The length of the shorter pipe is 60 cm. Find the length of the other. ltVeocity of sound in air = 330 ms^(-1) )

Calculate the frequency of fifth harmonic of a closed organ pipe of length 50cm, if the velocity of sound in air is 330 m/s.