A standing wave is set up in a string of a variable length and tension by a vibrator of variable frequency . Both ends of the string are fixed . When the vibrator has a frequency f , in a string of length L and under tension T , n antinodes are set up in the string is doubled , by what factor should the frequency be changed so that the same number of antinodes is produced? (b) If the frequency and lenght are held constant , what tension will produce n + 1 antinodes ? ( c) If the frequency is tripled and the length of the string is halved , by what factor should the tension be changed so that twice as many antinodes are produced ?

The frequency of vibration of string depends on the length L between the nodes, the tension F in the string and its mass per unit length m. Guess the expression for its frequency from dimensional analysis.

What are the factors on which the frequency of vibration of a stretched string depends ? Explain.

Derive an expression for the velocity of pulse in a in stretched in string under a tension T and mu is the mass per unit length of the sting.

The frequency of vibration (v) of a string may depend upon length (I) of the string, tension (T) in the string and mass per unit length (m) of the string. Using the method of dimensions, derive the formula for v.

In sonometer experiment , the string of length 'L' under tension vibrates iin second overtone between two bridges. The amplitude of vibration is maximum at

There are two strings of same material same diameter and length l and 2l stretched under same tension . If the strings are plucked and released, velocities of transverse waves on the two strings will be in the ratio