The equation `y=a sin 2 pi//lamda (vt -x)` is expression for :-

A transverse wave is represented by the equation y=y_0sin.(2pi)/(lamda)(vt-x) For what value of lamda , the maximum particle velocity equal to two times the wave velocity?

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A traverse wave is repersented by the equation y=y_(0)sin(2pi)/(lambda)(vt-x) For what value of lambda the maximumn particle velocity equal to two times the wave velocity

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-

The equation 2 sin^(2) (pi/2 cos^(2) x)=1-cos (pi sin 2x) is safisfied by