Prove analytically that in the case of a closed organ pipe of length L the frequencies of the vibrating air column are given by `v = (2n + 1) (v//4L)`, where n is an integer.

Prove analytically that in the case of a closed organ pipe of length I, the frequencies of the vibrating air column are given by nu =(2n + 1)(v//4L) , where n is an integer.

Prove analytically that in the case of an open organ pipe of length L the frequencies of vibrating air column are given by v=n(v//2L) , where n is an integer.

When a closed organ pipe of length l if the velocity of sound is v then the fundamental frequency will be

An open and closed organ pipe have the same length the ratio pth mode of frequency of vibration of air in two pipe is

In an open end organ pipe of length l if the speed of sound is V then the fundamental frequency will be

The third overtone of an open organ pipe of length l_(0) has the same frequency as the third overtone of a closed pipe of length l_(c) . The ratio l_(0)//l_(c) is equal to

An open organ pipe of length L vibrates in second harmonic mode. The pressure vibration is maximum

The first overtone of an open organ pipe(of length L_(0) ) beats with the first overtone of a closed organ pipe(of length L_(c) ) with a beat frequency of 10Hz.The fundamental frequency of the closed pipe is 110Hz .If the speed of sound is 330ms then fundamental frequency of open pipe is ?

The frequency of the third overtone of a closed pipe of length L_(c) is the same as the frequency of the sixth overtone of an open pipe of the length L_(o). Then