Derive an expression for the nth mode of vibration in case of a closed end organ pipe. Hence give the value of `v_1 :v_2 :v_3`.

Modes of vibration in a closed organ pipe are represented by –

Diagrammatically show first two modes of vibrations in case of an open organ pipe and write the ratio of their frequencies

If the end correction of closed organ pipe is 0.3 cm then the diameter of the tube will be

In the case of vibration of closed end organ pipe in fundamental mode of vibratin, the pressure id maximum at

An open organ pipe has fundamental frequency 300Hz.The first overtone of the open organ pipe is the same as the first overtone of a closed organ pipe. The length of the closed organ pipe is (v_(sound)=330m/s) (A) 10cm (B) 41cm (C) 82cm (D) 164cm

Two vibrating string of same length, same cross section area and stretched to same tension is made of meterials with densities rho and 2rho . Each string is fixed at both ends If v_0 represents the fundamental mode of vibration of the one made with density rho and v_2 for another Then v_1//v_2 is:

Assertion: An open organ pipe of certain length has the same fundamental frequency as closed organ pipe of half the length. Reason : In case of an open organ organ pipe, at both the ends antinodes are formed while in case of closed organ pipe, at one end antinode and at the other end node is formed.