Prove analytically that in the case of an open organ pipe of length L the frequencies of vibrating air column are given by `v=n(v//2L)` , where n is an integer.

Prove analytically that in the case of a closed organ pipe of length L the frequencies of the vibrating air column are given by v = (2n + 1) (v//4L) , where n is an integer.

Prove analytically that in the case of a closed organ pipe of length I, the frequencies of the vibrating air column are given by nu =(2n + 1)(v//4L) , where n is an integer.

For an open organ pipe of length l the wavelength of the fundamental note is equal to-

In open organ pipe, if fundamental frequency is n then the other frequencies are

An open and closed organ pipe have the same length the ratio pth mode of frequency of vibration of air in two pipe is

If the length of an open organ pipe is 33.3 cm, then the frequency of fifth overtone is (v_(sound)=333ms^(-1))

In an open organ pipe, if the fundamental frequency is n, the overtones produced in it are in the ratio of-

In an open end organ pipe of length l if the speed of sound is V then the fundamental frequency will be