In a simple harmonic progressive wave, the maximum particle velocity is twice the wave velocity. If `lamda` is the wavelength, then its amplitude is given by

If the maximum particle velocity is 4 times of the wave velocity then relation between wavelength and amplitude is

The maximum particle velocity in a wave motion is half the wave velocity. Then, the amplitude of the wave is equal to

S_(1) : The particles speed can never be equal to the wave speed in sine wave if the amplitude is less then wavelength divided by 2pi . S_(2) : In transverse wave of amplitude A, the maximum particle velocity is four times its wave velocity. Then, the wave length of the wave is piA S_(3) : the phase difference between two points separated by 1m in a wave of frequency 120 Hz is 90^(@) . the velocity of the wave is 480 m/s

A simple harmonic wave is represent by the relation y(x,t)=a_(0) sin 2pi(vt-(x)/(lambda)) if the maximum particle velocity is three times the wave velocity, the wavelength lambda of the wave is

When a simple harmonic progressive wave is propogating the medium, all the particles of the medium vibrate with

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

If amplitude of velocity is V_0 then the velocity of simple harmonic oscillator at half of the amplitude is

Wave velocity & particle velocity from wave equation

The angle between wave velocity and particle velocity in a travelling wave be