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ERRORLESS HINDI-अनिश्चित समाकलन -MULTIPLE CHOICE QUESTIONS (मूलभूत समाकलन )
- int (1)/(x^(2)) (2x + 1)^(3) dx =
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- int (5(x^(6) + 1))/(x^(2) + 1)dx =
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- int (x^(2))/(x^(2)+4) dx =
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- int (dx)/(sin x + sqrt(3) cos x) =
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- int (x^(2) + x - 6)/((x-2)(x-1))dx =
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- int (dx)/(4 cos^(3) 2x - 3 cos 2x) =
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- int (sin 3x)/(sin x)dx =
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- int (cos 2x)/(cos x) dx का मान होगा:
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- int (sin x + "cosec x")/(tan x) dx =
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- int (1)/(sqrt(1+sin x))dx =
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- int {1 + 2 tan x (tan x + sec x)}^(1//2) dx =
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- int (2x)/((2x + 1)^(2))dx =
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- यदि f'(x) = (1)/(x) + x और f(1) = (5)/(2), तब f(x) =
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- int (1-tan x)/(1 + tan x) dx =
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- int ((x-a)/(x) - (x)/(x+a))dx बराबर है
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- int (2x + sin 2x)/(1 + cos 2x)dx बराबर है
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- int (1)/(sin x cos x)dx बराबर है
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- int (e^(6 log x) - e^(5 log x))/(e^(4 log x)-e^(3 log x))dx =
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- int (cos 2x - cos 2 theta)/(cos x - cos theta)dx =
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- int (x^(3))/(x+1)dx =
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