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ERRORLESS HINDI-अनिश्चित समाकलन -MULTIPLE CHOICE QUESTIONS (प्रतिस्थापन द्वारा समाकलन )
- int (sin 2x)/(a^(2) + b^(2) sin^(2)x) dx =
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- int ("cosec x")/(cos^(2) (1+"log tan"(x)/(2)))dx=
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- int (1)/(cos^(2) x(1-tanx)^(2))dx =
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- int (10x^(9) + 10^(x) log(e) 10)/(10^(x) + x^(10))dx =
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- int (1)/((e^(x)+e^(-x))^(2)) dx =
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- int (cos 2x)/((cos x + sin x)^(2))dx =
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- int cos^(3) x e^(log(sin x))dx =
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- int (x)/(1 + x^(4)) dx =
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- int (e^(-x))/(1+e^(x)) dx =
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- int (1)/(sqrt(1-e^(2x)))dx =
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- int (3x^(2))/(sqrt(9 - 16x^(6))) dx =
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- int cos x sqrt(4 - sin^(2)x) dx =
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- int sec^(2//3) "x cosec"^(4//3) x dx =
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- int cos^(5) x dx =
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- int (dx)/(1+tan x) =
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- int (d theta)/(sin theta cos^(3) theta) =
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- int (1)/(cos^(-1) x. sqrt(1-x^(2)))dx =
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- int x^(3) e^(3x^(2)+5) dx का मान ज्ञात करने के लिए सरलतम तरीका है
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- int x(x^(x))^(x) (2 log x + 1) dx =
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- int (x^(3) dx)/(1+x^(8)) =
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