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ERRORLESS HINDI-अनिश्चित समाकलन -MULTIPLE CHOICE QUESTIONS (प्रतिस्थापन द्वारा समाकलन )
- int (3x^(2))/(sqrt(9 - 16x^(6))) dx =
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- int cos x sqrt(4 - sin^(2)x) dx =
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- int sec^(2//3) "x cosec"^(4//3) x dx =
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- int cos^(5) x dx =
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- int (dx)/(1+tan x) =
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- int (d theta)/(sin theta cos^(3) theta) =
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- int (1)/(cos^(-1) x. sqrt(1-x^(2)))dx =
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- int x^(3) e^(3x^(2)+5) dx का मान ज्ञात करने के लिए सरलतम तरीका है
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- int x(x^(x))^(x) (2 log x + 1) dx =
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- int (x^(3) dx)/(1+x^(8)) =
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- int (x^(3) sin [tan^(-1) (x^(4))])/(1 + x^(8))dx =
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- int (dx)/(e^(-2x) (e^(2x) + 1)^(2))=
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- int tan^(4)x dx का मान ज्ञात कीजिए ।
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- int tan x sec^(2) x sqrt(1-tan^(2) x) dx =
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- int (sin 2 x)/(sin 5x sin 3x) dx =
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- int (e^(x)dx)/(sqrt(1-e^(2x)))=
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- int (1)/(log a) (a^(x)cos a^(x)) dx =
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- int (sin x dx)/((a + b cos x)^(2))=
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- int (1)/(x^(3)) [log x^(x)]^(2) dx=
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- int (dx)/(x log x log (log x)) =
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