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int (1)/((x^(2)+a^(2))(x^(2)+b^(2)))dx =...

`int (1)/((x^(2)+a^(2))(x^(2)+b^(2)))dx =`

A

`(1)/((a^(2)-b^(2)))[(1)/(b)tan^(-1)((x)/(b))-(1)/(a) tan^(-1) ((x)/(a))] + c`

B

`(1)/((b^(2)-a^(2)))[(1)/(b)tan^(-1) ((x)/(b))-(1)/(a)tan^(-1)((x)/(a))]+c`

C

`(1)/(b)tan^(-1) ((x)/(b)) - (1)/(a) tan^(-1) ((x)/(a))+c`

D

`(1)/(a)tan^(-1) ((x)/(a)) - (1)/(b) tan^(-1) ((x)/(b)) + c`

लिखित उत्तर

Verified by Experts

The correct Answer is:
A
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