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ERRORLESS HINDI-अनिश्चित समाकलन -EXERCISE
- int ((x+1)^(2)dx)/(x(x^(2)+1)) =
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- यदि समाकलन int (5 tan x)/(tan x - 2) dx = x + a In |sin x - 2 cos x| +...
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- int (5x dx)/((1-x)^(3)) बराबर है
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- यदि int f(x) dx = Psi (x) है, तो int x^(5) f(x^(3)) dx बराबर है
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- जब x gt 0, तब int cos^(-1) ((1-x^(2))/(1+x^(2)))dx =
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- int 2x cos^(3) x^(2) sin x^(2) dx =
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- int sec^(4) x tan x dx =
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- int e^(-x) "cosec"^(2) (2e^(-x) + 5) dx =
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- int (cos 2x + x + 1)/(x^(2)+ sin 2x + 2x) dx =
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- int (1+tan x)/(x+log sec x) dx =
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- int ((x+1)(x+log x)^(2))/(x)dx =
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- int (1+x^(2))/(sqrt(1-x^(2)))dx =
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- int (cos x - sin x)/(1+sin 2 x) dx=
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- int x^(3) sqrt(3+5x^(4)) dx =
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- int sqrt((x)/(a^(3) - x^(3)))dx =
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- int (1)/(x^(2) sqrt(1+x^(2)))dx =
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- int (1)/((x^(2)-1) sqrt(x^(2)+1))dx =
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- int (log (x + sqrt(1 + x^(2))))/(sqrt(1 + x^(2)))dx =
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- int (x^(5) dx)/(sqrt((1+x^(3)))) =
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- int ((x^(4) - x)^(1//4))/(x^(5))dx =
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