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ERRORLESS HINDI-अनिश्चित समाकलन -EXERCISE
- int (1)/(x^(2) sqrt(1+x^(2)))dx =
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- int (1)/((x^(2)-1) sqrt(x^(2)+1))dx =
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- int (log (x + sqrt(1 + x^(2))))/(sqrt(1 + x^(2)))dx =
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- int (x^(5) dx)/(sqrt((1+x^(3)))) =
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- int ((x^(4) - x)^(1//4))/(x^(5))dx =
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- int (dx)/(sin (x-a)sin(x-b))=
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- int (x^(2)-1)/(x^(3)sqrt(2x^(4) - 2x^(2) + 1))dx =
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- int (1)/([(x-1)^(3)(x+2)^(5)]^(1//4))dx का मान है
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- int (dx)/(x sqrt(x^(4) - 1))=
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- यदि int (1)/((1 + x) sqrt(x)) dx = f(x) + A, जहाँ A कोई स्वेच्छ नियतां...
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- int x cos x^(2) dx =
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- int (x^(2) tan^(-1) x^(3))/(1+x^(6))dx =
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- int (x^(2) + 1)/(x(x^(2) - 1))dx =
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- int (e^(2x) + 1)/(e^(2x) - 1) dx =
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- int (1+(1)/(x^(2)))e^((x-(1)/(x)))dx =
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- int cos^(-3//7)x sin^(-11//7)x dx =
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- int (1)/(1+cos x + sin x)dx =
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- int ((sin theta + cos theta))/(sqrt(sin 2 theta))d theta =
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- I = int (dx)/((1+e^(x))(1+e^(-x))) का क्या मान है
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- int x^(x) (1 + log x) dx =
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