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ERRORLESS HINDI-अनिश्चित समाकलन -EXERCISE
- यदि int (1)/((1 + x) sqrt(x)) dx = f(x) + A, जहाँ A कोई स्वेच्छ नियतां...
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- int x cos x^(2) dx =
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- int (x^(2) tan^(-1) x^(3))/(1+x^(6))dx =
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- int (x^(2) + 1)/(x(x^(2) - 1))dx =
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- int (e^(2x) + 1)/(e^(2x) - 1) dx =
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- int (1+(1)/(x^(2)))e^((x-(1)/(x)))dx =
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- int cos^(-3//7)x sin^(-11//7)x dx =
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- int (1)/(1+cos x + sin x)dx =
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- int ((sin theta + cos theta))/(sqrt(sin 2 theta))d theta =
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- I = int (dx)/((1+e^(x))(1+e^(-x))) का क्या मान है
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- int x^(x) (1 + log x) dx =
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- int e^(3 log x) (x^(4)+1)^(-1) dx =
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- int "cosec"^(4)x dx =
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- यदि int f(x) dx = g(x), तब int f^(-1) (x) dx =
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- int (sin^(-1)x)/(sqrt(1-x^(2)))dx बराबर है जहाँ c स्वेच्छ अचर है
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- int (x)/(sqrt(4-x^(4)))dx =
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- int (sin x dx)/(3 + 4 cos^(2)x) =
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- int (dx)/(sqrt(x) (x+9))dx का मान है
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- int {((log x-1))/(1+(log x)^(2))}^(2)dx =
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- यदि int (cos 4x + 1)/(cot x - tan x) dx = k cos 4x + c तब
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