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ERRORLESS HINDI-अनिश्चित समाकलन -EXERCISE
- यदि I(n) = int (log x)^(n) dx, "तब" I(n) + nI(n-1)=
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- int e^(x//2) sin ((x)/(2)+(pi)/(4))dx =
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- यदि int (2x + 3)/(x^(2)-5x+6)dx = 9 In (x-3)-7 In (x-2) + A, तब A =
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- int (dx)/(2+cos x) =
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- int (x)/(x^(4)+x^(2)+1)dx =
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- int (dx)/((sin x + sin 2x))=
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- यदि int (2x + 3)/((x-1)(x^(2)+1))dx = log(e) {(x-1)^((5)/(2)) (x^(2) +...
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- यदि int ((2x^(2)+1)dx)/((x^(2) - 4)(x^(2)-1))=log[((x+1)/(x-1))^(a) ((...
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- int sqrt(1+"cosec x") dx =
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- int root(3)(x) root(7)(1 + root(3)(x^(4))) dx =
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- int (sec x)/(sqrt(sin (2x + alpha) + sin alpha))dx =
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- int (d^(2))/(dx^(2))(tan^(-1)x)dx =
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- int (1)/(sqrt(8+2x-x^(2)))dx=
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- int ((4e^(x)-25)/(2e^(x)-5))dx = Ax + B log (2e^(x) - 5)+c तो
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- int (1)/(x log x^(2))dx =
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- int ((1+x)e^(x))/(cot (xe^(x)))dx बराबर है
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- int (4e^(x))/(2e^(x)-5e^(-x))dx =
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- int (sqrt(x) + (1)/(sqrt(x)))^(2)dx =
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- int (x^(n-1))/(x^(2n)+a^(2))dx =
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- int ((x+1)^(2))/(x(x^(2)+1))dx =
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