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if the diameter of atom is 0.15 nm c...

if the diameter of atom is 0.15 nm calculate the number of carbon atom which can be placed side by side in a straight line across length of scale of length 20 cm long

Text Solution

Verified by Experts

20 cm = 20 `xx 10^(7) nm` length
diameter of carbon atom =0.15 nm
So 0.15 nm space = 1 carbon atom
20 `xx 10^(7) nm` space = (?) carbon atom
No of carbon atoms = `(20 xx 10^(7) nm xx 1)/( 0.15 nm) `
=133.3 `xx10^(7)`
`1.333 xx 10^(9)` carbon atoms
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