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2xx 10^(8) atoms of carbon are arrange...

`2xx 10^(8) ` atoms of carbon are arranged side by side caculate the radius of carbon atom if the length of this arrangement is 2.4 cm .

Text Solution

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Where `2xx 10^(8) ` carbon atom = 2.4 cm
1 carbon atom = (?) cam
diameter of carbon = `(1xx 2.4 cm)/( 2xx 10^(8)) = 1.2 xx 10^(8) cm`
radius of carbon = `(1.2xx 10^(8) cm)/( 2 ) `
`6.0 xx 10^(9) cm`
`6.0 xx 10^(9) xx 10^(7) nm`
`-0.06 nm`
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