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The diameter of zinc atom is 2.6 A .C...

The diameter of zinc atom is 2.6 A .Calcuate ( a) radius of zinc atom in pma and ( b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Text Solution

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Radius of zinc = `("Diameter ")/( 2 ) = (2.6 A )/ (2 ) = 1.3A`
`1 A = 1 xx 10^(2)` pm
Sio `1.3A = 1.3 xx 10^(2)` pm
Radius = 130 pm and diameter -260 pm
Number of zinc atom = Length , Diameter
`- = (1.6 xx 10^(18) pm)/( 260 pm)`
`=6.154 xx 10^(7)` atom
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