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Calculate energy of one mole of phot...

Calculate energy of one mole of photons of radiation whose frequency is `5xx 10^(14) Hz`
(h = 6.626 `xx 10^(34)j ` )

Text Solution

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E= hv = (6.626 `xx10^(34)`J s ) `xx (5 xx 10^(14) s^(-1))`
1 mole phton n= 6.626 `xx10^(34) js`
E=(6.022 `xx 10^(23)` ) (3.313 `xx 10^(19) ` J)
E = 199. 51 kJ `mol^(-1)`
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