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The longest wavelength double absorptio...

The longest wavelength double absorption transition is observed at 589 and 589 nm Calculate the frequency of each transition and energy difference between two excited states.

Text Solution

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First line wavelength
`lambda_(1) = 589 nm = 589 xx 10^(9) m= 589 xx 10^(7) m`
frequency `v_(1) = (c )/(lambda) = (3.0 xx 10^(8) ms^(_1))/( 5.89 xx 10^(7) m)`
`=5.0934 xx 10^(14) s^(-1)`
Second line wavelength
`lambda_(2) = 589 nm = 589 .6 xx 10^(9) nm = 5.896 xx 10^(7) m`
Difference of doublet frequency `(v_(1) -v_(2)) Delta v`
and energy difference `Delta E = hDelta E`
`(6.626 xx 10^(34 ) js) ( 0.0052 xx 10^(14)s^(-1))`
`=0.03446 xx 10^(20) J = 3.446 xx 10^(22) J`
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