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The ejection of the photoelectron from...

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 eV with the radiation 256.7 nm is used .Calculated the work function silver metal.

Text Solution

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Work function (W ) = minimum energy required for ejection of the photoelectron `E_(0) = hv_(0)`
Applying wavelength `(lambda) = 256 .7 nm`
Applying voltage -= E
KE= 0.35 eV
c= 3.0 `xx 10^(8) M`
`h= 6.626 xx 10^(34) Js`
`1eV = 1.602 xx 10^(19) J`
Applying energy (E ) = hv `= (hc )/(lambda)`
`=(6.626 xx 10^(34) J s xx 3xx 10^(8) m)/( 2.567 xx 10^(7) m)`
`7.7437 xx 10^(19) J`
`=(7.7437 xx 10^(19))/( 1.602 xx 10^(19)) =4.8338` eV apply energy
but E =`(E_(0) = KE)`
`E_(0) = E - KE`
`=4.833 8 eV -0.35 eV`
`=4.4838 = 4.48 eV`
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